 Program to find the rate percentage from compound interest of consecutive years

Given two integers N1 and N2 which is the Compound Interest of two consecutive years. The task is to calculate the rate percentage.

Examples:

Input: N1 = 660, N2 = 720
Output: 9.09091 %

Input: N1 = 100, N2 = 120
Output: 20 %

Approach: The rate percentage can be calculated with the formula ((N2 – N1) * 100) / N1 where N1 is the compound interest of some year and N2 is the compound interest for the next year.

Let us consider the 1st Example:
The difference between the Compound interest in the two consecutive years is because of the interest received on the previous year interest. Therefore,
–> N2 – N1 = N1 * (Rate / 100)
–> 720 – 660 = 660 * (Rate / 100)
–> (60 / 660) * 100 = Rate
–> Rate = (100 / 11) = 9.09% (Approx)

Below is the implementation of the above approach:

 #include using namespace std;    float Rate(int N1, int N2) {     float rate = (N2 - N1) * 100 / float(N1);        return rate; }    int main() {     int N1 = 100, N2 = 120;        cout << Rate(N1, N2) << " %";        return 0; } If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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